Same-Origin AJAX Request Using Vanilla JavaScript

πŸ‘‹ Ciprian on Tuesday, January 9, 2018 in Blog, JavaScript
Last modified on Friday, January 5, 2018

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This JavaScript function will send an AJAX request – GET or POST – with no third-party dependencies:

function soQuery(soMethod, soUri) {
    var xhttp = new XMLHttpRequest();

    xhttp.open(soMethod, soUri, true);

    if (soMethod === 'GET') {
        xhttp.send();
    } else if (soMethod === 'POST') {
        xhttp.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
        xhttp.onload = function () {
            // do something to response
            console.log(this.responseText);
        };
        xhttp.send('param1=param1value&param2=param2value&param3=param3value');
    }
}

// Usage
soQuery('GET', 'https://www.example.com/query.php');

Note that the URL should be on the same domain as the function caller.

Find more JavaScript tutorials, code snippets and samples here or more jQuery tutorials, code snippets and samples here.

Find more JavaScript tutorials, code snippets and samples here or more jQuery tutorials, code snippets and samples here.

πŸ‘‹ Added by Ciprian on Tuesday, January 9, 2018 in Blog, JavaScript. Last modified on Friday, January 5, 2018.

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